3. Show how you would synthesize the following compounds, starting with benzene or toluene and any necessary acyclic reagents. The compound B, on treatment with PCl 5, followed by reaction with H 2 / Pd(BaSO 4) gives compound C, which on reaction with hydrazine gives a cyclised compound D (C 14 H 10 N 2 ). As other answerers have said, the major product from those reagents plus an AlCl3 catalyst is isopropylbenzene, aka cumene. nitrobenzene + fuming sulfuric acid (d) benzene + CH3CH2COCl in the presence of (1) ALCl3 followed by (2) H2O. The isopropyl benzene results from a rearrangement of the initially formed propyl carbocation to the more stable isopropyl carbocation. nitrobenzene + ethyl chloride/AlCl3 (b). Check Answer a A hydride ion is H −. p-methylanisole + acetyl chloride + AlCl3 (c). This rearrangement is called a 1,2-hydride ion shift. One example is the formation of isopropyl benzene by the reaction of propyl chloride with benzene. This is the result of a carbocation rearrangement: CH3—CH2—CH2+ → CH3—CH+—CH3. Write a note on benzene is treated with acetyl chloride in the presence of alcl3 2 See answers biswalsandeep594 biswalsandeep594 Explanation: Explanation:AlCl3 is considered to be a Lewis Acid or in simpler words an “electron hungry species”. An organic compound A, C 8 H 4 O 3, in dry benzene in the presence of anhydrous AlCl 3 gives compound B. \[C_6H_6 + Cl_2 \rightarrow C_6H_5Cl + HCl\] or: The reaction with bromine. Acid chlorides react with benzene in presence of AlCl3 to introduce acyl group -COR. Compound X upon reaction with $\ce{Br2/Na2CO3}$, followed by heating at 473 K with moist KOH furnishes Y as the major product. (a). (A) benzoylchlorde (B) benzophenone (C) benzoicacid (D) benzbinacol (a.) Q. PARAGRAPH "X" Treatment of benzene with $\ce{CO/HCl}$ in the presence of anhydrous $\ce{AlCl3/CuCl}$ followed by reaction with $\ce{Ac2O/NaOAc}$ gives compound X as the major product. ethoxybenzene Benzene reacts with CH3Cl in the presence of anhydrous AlCl3 to form: Option 1) Chlorobenzene Option 2) Benzylchloride Option 3) Xylene Option 4) Toluene CH3Cl in the presence of anhydrous AlCl3 acts as alkylation agent and introduces an alkyl group.This reaction is known as Friedel-Craft s alkylation of benzene. (i) Benzene is treated with CH3CH2COCl + AlCl3 Here Friedel crafts acylation reaction takes place. Here CH3CH2COCl … The mechanism of this reaction – electrophilic substitution Benzene reacts with chlorine/bromine in the presence of halogen carriers such as aluminium chloride, AlCl3 to form chloro- or bromobenzene, One hydrogen atom in the benzene ring is substituted by the halogen. Reaction of X with $\ce{H2/Pd-C}$, followed by $\ce{H3PO4}$ … the starting material, benzene CH3Cl + AlCl3 CH3 CH3 CH3 CH3 CH3 etc. The halide which will not react with benzene in presence of anhydrous AlCl3 is (A) CH3CHClCH3 (B) C6H5CH2Cl (C) C6H5Cl (D) CH3CH2CH2Cl. Phosgene react with excess of benzene in presence of anhyd Alcl3 to give. Identify A, B, C, and D. Explain the formation of D from C. The reaction between benzene and chlorine in the presence of either aluminum chloride or iron gives chlorobenzene. The reaction between benzene and bromine in the presence of either aluminum bromide or iron gives bromobenzene. Use chlorine as an example of halogen: C6H6 + Cl2 → C6H5Cl + HCl .